Removing data points from a chart using vba | Excel forum

I am working on a template that graphs and compares data from multiple sources, I need to be able to use the graphs to see patterns in the data and also remove spikes or outliers from any one of 27 columns of data that create the separate charts.
So far I've been doing this manually but I've found some code that enables the user to select data points on a chart and parse the series name and data point to a message box to alert the user of the point selected.

The part I'm stuck with is getting a cell address from the series name and data point so I can write a section of code to clear the contents of the cell, and thereby remove the data point from the chart.

Here's the code so far. It works with the chart sheet that becomes active when the user selects it.

Private Sub EvtChart_MouseUp(ByVal Button As Long, ByVal Shift As Long, _
ByVal x As Long, ByVal y As Long)
'extracted and modified from http://www.computorcompanion.com/LPMArticle.asp?ID=221

Dim ElementID As Long
Dim a As Long
Dim b As Long
Dim msg As String
Dim myX As Date
Dim myY As Double
Dim Answer As Integer
Dim Counter As Integer
Dim QAFDest As Range
Dim NoRows As Integer

With ActiveChart
' Pass x & y, return ElementID and Args
.GetChartElement x, y, ElementID, a, b

If ElementID = xlSeries Then
If b > 0 Then
' Extract x value from array of x values
myX = WorksheetFunction.Index _
(.SeriesCollection(a).XValues, b)
' Extract y value from array of y values
myY = WorksheetFunction.Index _
(.SeriesCollection(a).Values, b)


' Display message box with point information
msg = "You are about to remove the following point from data Series " & vbCrLf _
& """" & .SeriesCollection(a).Name & """" & vbCrLf _
& "Point " & b & vbCrLf _
& "Value = " & myY & vbCrLf _
& "Continue?"

If MsgBox(msg, vbOKCancel) = vbOK Then
'Sheet4.Cells(b, ?).ClearContents
End If
End If
End If
End With
End Sub

I've been hunting for a solution on the internet and baking my noodle for a almost a week now but I'm no closer to finding the answer. I think I must be missing something obvious. Any help would be gratefully received!

Thanks
Sarah